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411 समाचार
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411 REFERENCE · Wikibooks

Linear Algebra and the C Language/a0k8

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__NOTOC__ Install and compile this file in your working directory. /* ------------------------------------ */ /* Save as : c00b.c */ /* ------------------------------------ */ #include "v_a.h" /* ------------------------------------ */ int main(void) { time_t t; srand(time(&t)); double ta[R3*C4]={ 1,0,0, 1, 0,1,0, .5, 0,0,1, 1./3.}; double **T = ca_A_mR(ta, i_mR(R3,C4)); double **A = rE_mR( i_mR(R3,C3),999.,1E-3); double **AT = mul_mR(A,T, i_mR(R3,C4)); double **Ab = gj_TP_mR(c_mR(AT, i_Abr_Ac_bc_mR(R3,C3,C1))); clrscrn(); printf(" You want to create this nonlinear system of equations :\n"); printf(" (X, Y, Z not 0)\n"); printf("\n"); printf(" a 1/X + b 1/Y + c 1/Z = d \n"); printf(" e 1/X + f 1/Y + g 1/Z = h \n"); printf(" i 1/X + j 1/Y + k 1/Z = l \n"); printf("\n"); printf(" With 1/X = 1, 1/Y = .5, 1/Z = .333333 \n"); printf("\n"); printf(" In fact, you want to find a matrix, \n"); printf(" which has this reduced row-echelon form :\n\n" "Ab:"); p_mR(T, S5,P3,C6); stop(); clrscrn(); printf(" If :\n\n A = rE_mR(i_mR(R3,C3),999.,1E-3); "); p_mR(A, S5,P3,C6); printf(" And :\n\n T:"); p_mR(T, S5,P3,C6); printf(" I suggest this matrix : AT = Ab\n\n" " Ab:"); p_mR(AT, S5,P3,C6); stop(); clrscrn(); printf("\n With the Gauss Jordan function :\n" "Ab:"); p_mR(Ab, S5,P3,C6); stop(); f_mR(Ab); f_mR(A); f_mR(T); f_mR(AT); return 0; } /* ------------------------------------ */ /* ------------------------------------ */ Screen output example: You want to create this nonlinear system of equations : (X, Y, Z not 0) a 1/X + b 1/Y + c 1/Z = d e 1/X + f 1/Y + g 1/Z = h i 1/X + j 1/Y + k 1/Z = l With 1/X = 1, 1/Y = .5, 1/Z = .333333 In fact, you want to find a matrix, which has this reduced row-echelon form : Ab: +1.000 +0.000 +0.000 +1.000 +0.000 +1.000 +0.000 +0.500 +0.000 +0.000 +1.000 +0.333 Press return to continue. If : A = rE_mR(i_mR(R3,C3),999.,1E-3); -0.614 +0.781 +0.598 +0.575 -0.753 +0.944 -0.667 -0.312 +0.772 And : T: +1.000 +0.000 +0.000 +1.000 +0.000 +1.000 +0.000 +0.500 +0.000 +0.000 +1.000 +0.333 I suggest this matrix : AT = Ab Ab: -0.614 +0.781 +0.598 -0.024 +0.575 -0.753 +0.944 +0.513 -0.667 -0.312 +0.772 -0.566 Press return to continue. With the Gauss Jordan function : Ab: +1.000 -0.000 -0.000 +1.000 +0.000 +1.000 +0.000 +0.500 +0.000 +0.000 +1.000 +0.333 Press return to continue.