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411 समाचार
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411 REFERENCE · Wikibooks

Solutions To Mathematics Textbooks/Calculus Early Transcendentals (6th) (0495011665)/Chapter 1.2

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9 is a cubic, so must be of the form . Therefore, , so now Looking at other values: Try to solve simulatenously: , thus . , thus . Thus, Solve simultaneous equation: therefore . If then: , thus . Therefore, we have and our function is given by .