Computer Programming/Physics/Position of an accelerating body function (constant acceleration)

<Wikisource:Source code The position of an accelerating body is a mathematical function expressed as:   if a is constant. a is acceleration v is initial velocity t is time s is starting position It is expressed below in various programming languages Assembly Intel x86 (32-bit) ; eax = a, ebx = v, ecx = t, edx = s push edx mul ecx mul ecx shr eax,1 add DWORD PTR [esp],eax mov eax,ebx mul ecx add DWORD PTR [esp],eax pop eax Intel x86 (32-bit) using the FPU somewhere in the data section: a dd 0.0 ; m*s^-2 s dd 0.0 ; m v dd 0.0 ; m*s^-1 t dd 0.0 ; s half dd 0.5 ; scalar code: push 40000000h fld DWORD PTR [esp] fld t fyl2x fld st(0) frndint fsub st(1),st(0) fxch st(1) f2xm1 fld1 fadd fscale fstp st(1) fld a fmul fld half fmul fld v fld t fmul fadd fld s fadd add esp,4 ffree st(0) C inline float PositionofAcceleratingBody(float a, float v, float t, float s) { return .5 * a * t * t + v * t + s; } C++ template<class Vector,class Number> inline Vector PositionofAcceleratingBody(Vector a,Vector v0,Vector s0,Number t) { return (0.5*a*t+v0)*t+s0; } Delphi function PositionofAcceleratingBody(real a, v, t, s): real; begin result := .5 * a * t * t + v * t + s; end; PHP function PositionofAcceleratingBody($a, $v, $t, $s) { return .5 * $a * $t * $t + $v * $t + $s; } Java public double positionOfAcceleratingBody(double a, double v, double t, double s){ return a * t * t / 2 + v * t + s; } Python def positionOfAcceleratingBody(a, v, t, s): return .5 * a * (t ** 2) + v * t + s