Skip to main content

  | मौसम…

411 समाचार
Public archive edition · Attributed source reporting with original dates · AI drafts are excluded

411 REFERENCE · Wikibooks

Topics in Abstract Algebra/Non-commutative rings

Reference material by Wikibooks contributors. This retains its source identity and is not 411 news reporting.

A ring is not necessarily commutative but is assumed to have the multiplicative identity. Proposition Let be a simple ring. Then: every morphism is either zero or an isomorphism. (Schur's lemma) Theorem Levitzky Let be a right noetherian ring. Then every (left or right) nil ideal is nilpotent.