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1897 Iowa gubernatorial election
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1897 Iowa gubernatorial election Iowa Presidential no 1895 Iowa gubernatorial election 1895 1899 Iowa gubernatorial election 1899 November 2, 1897 File:Leslie Shaw, Bain photo portrait (cropped).jpg L. M. Shaw Republican Party (United States) 224,729 51.27% Frederick Edward White (1).png Frederick Edward White Democratic Party (United States) 194,853 44.46% 1897 Iowa gubernatorial election results map by county.svg 240px County results
Shaw: #FFB2B2 40–50% #e27f7f 50–60% #d75d5d 60–70% #D72F30 70–80%White: #A5B0FF 40–50% #7996E2 50–60% Governor Francis M. Drake Republican Party (United States) L. M. Shaw Republican Party (United States)
The 1897 Iowa gubernatorial election was held on November 2, 1897. Republican nominee L. M. Shaw defeated Democratic nominee Frederick Edward White with 51.27% of the vote.
General election
Candidates
Major party candidates
L. M. Shaw, Republican
Frederick Edward White, Democratic
Other candidates
S. P. Leland, Prohibition
Charles Lloyd, People's
John Cliggett, National Democratic
M. J. Kremer, Socialist Labor
Results
1897 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 August 8, 2020 Kalb Deborah 24 December 2015
Republican Party (United States) L. M. Shaw 224,729 51.27%
Democratic Party (United States) Frederick Edward White 194,853 44.46%
Prohibition Party S. P. Leland 8,243 1.88%
People's Party (United States) Charles Lloyd 5,295 1.21%
Independent politician John Cliggett 4,296 0.98%
Socialist Labor Party of America M. J. Kremer 876 0.20%
29,876
Republican Party (United States)
References
collapsed
1897
Iowa