1896 United States presidential election in Rhode Island

none June 2025 September 2023 1896 United States presidential election 1896 United States presidential election in Rhode Island Rhode Island 1882 presidential no 1892 United States presidential election in Rhode Island 1892 1900 United States presidential election in Rhode Island 1900 November 3, 1896 x200px William McKinley by Courtney Art Studio, 1896 (cropped).jpg William McKinley Republican Party (United States) Ohio Garret Hobart 4 37,437 68.33% William Jennings Bryan 2 (cropped).jpg William Jennings Bryan Democratic Party (United States) Nebraska Arthur Sewall 0 14,459 26.39% 250px County results 250px Municipality results McKinley #e27f90 50–60% #cc2f4a 60–70% #d40000 70–80% #aa0000 80–90% #800000 90–100% President Grover Cleveland Democratic Party (United States) William McKinley Republican Party (United States) The 1896 United States presidential election in Rhode Island took place on November 3, 1896, as part of the 1896 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won the state by a wide margin of 41.94%. Bryan, running on a platform of free silver, appealed strongly to Western miners and farmers in the 1896 election, but had little appeal in Northeastern states like Rhode Island. With 68.33% of the popular vote, Rhode Island would be McKinley's fourth strongest victory in terms of percentage in the popular vote after Vermont, neighboring Massachusetts and New Hampshire.https://uselectionatlas.org/RESULTS/stats.php?year=1896&f=1&off=0&elect=0 1896 Presidential Election Statistics Dave Leip’s Atlas of U.S. Presidential Elections 2018-03-05 Bryan would lose Rhode Island to McKinley again four years later and would later lose the state again in 1908 to William Howard Taft. Results 1896 United States presidential election in Rhode Island1896 Presidential General Election Results - Rhode Island http://uselectionatlas.org/RESULTS/state.php?year=1896&fips=44&f=1&off=0&elect=0 U.S. Election Atlas 23 December 2013 Republican Party (United States) William McKinley Ohio Garret Hobart New Jersey 37,437 68.33% 4 100.00% Democratic Party (United States) William Jennings Bryan Nebraska Arthur Sewall Maine 14,459 26.39% 0 0.00% National Democratic Party (United States) John McAuley Palmer Illinois Simon Bolivar Buckner Kentucky 1,166 2.13% 0 0.00% Prohibition Party Joshua Levering Maryland Hale Johnson Illinois 1,160 2.12% 0 0.00% Socialist Labor Party of America Charles Horatio Matchett New York Matthew Maguire New Jersey 558 1.02% 0 0.00% N/A Others Others 5 0.01% 0 0.00% 54,785 100.00% 4 100.00% See also United States presidential elections in Rhode Island References Rhode Island 1896 Category:1896 Rhode Island elections