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1828 United States presidential election in Illinois
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1828 United States presidential election in Illinois presidential no 1824 United States presidential election in Illinois 1824 1832 United States presidential election in Illinois 1832 October 31 – December 2, 1828 x200px Andrew Jackson by Thomas Sully (Cropped).jpg Andrew Jackson Democratic Party (United States) Tennessee John C. Calhoun 3 9,560 67.22% Portrait of John Quincy Adams (DRR) (Cropped).jpg John Quincy Adams National Republican Party (United States) Massachusetts Richard Rush 0 4,662 32.78% 1828 United States presidential election in Illinois results map by county.svg 180px County results
Jackson
#86b6f2 50–60%
#4389e3 60–70%
#1666CB 70–80%
#0645B4 80–90%
#002B84 90–100%
Adams
#FFDDA4 50–60%
#FFCD79 60–70%
No Data/Vote
#808080
The 1828 United States presidential election in Illinois took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Illinois voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Illinois by a margin of 34.44%.
Results
1828 United States presidential election in Illinois1828 Presidential General Election Results - Illinois http://uselectionatlas.org/RESULTS/state.php?year=1828&f=1&off=0&elect=0&fips=17&submit=Retrieve U.S. Election Atlas 28 February 2013PartyCandidateVotesPercentageElectoral votes Democratic Andrew Jackson 9,560 67.22% 3 National Republican John Quincy Adams (incumbent) 4,662 32.78% 0 Totals 14,222 100.0% 3
See also
United States presidential elections in Illinois
References
Illinois
1828
Category:1828 Illinois elections