1868 United States presidential election in New Jersey

none June 2025 September 2023 1868 United States presidential election 1868 United States presidential election in New Jersey presidential no 1864 United States presidential election in New Jersey 1864 1872 United States presidential election in New Jersey 1872 November 3, 1868 x200px Hon. Horatio Seymour, N.Y - NARA - 528568 (cropped).jpg Horatio Seymour Democratic Party (United States) New York Francis Preston Blair Jr. 7 83,001 50.88% Ulysses S Grant by Brady c1870-restored (3x4 crop).jpg Ulysses S. Grant Republican Party (United States) Illinois Schuyler Colfax 0 80,131 49.12% 1868 United States presidential election in New Jersey results map by county.svg 350px County results Seymour #86b6f2 50–60% #4389e3 60–70% Grant #e27f90 50–60% #CC2F4A 60–70% President Andrew Johnson Democratic Party (United States) Ulysses S. Grant Republican Party (United States) The 1868 United States presidential election in New Jersey took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president. New Jersey voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won by a narrow margin of 1.76%. Results 1868 United States presidential election in New Jersey1868 Presidential General Election Results - New Jersey http://uselectionatlas.org/RESULTS/state.php?year=1868&fips=34&f=1&off=0&elect=0 Democratic Party (United States) Horatio Seymour New York Francis Preston Blair Jr. Missouri 83,001 50.88% 7 100.00% Republican Party (United States) Ulysses S. Grant Illinois Schuyler Colfax Indiana 80,131 49.12% 0 0.00% 163,132 100.00% 7 100.00% See also United States presidential elections in New Jersey References New Jersey 1868 Category:1868 New Jersey elections