1895 Rhode Island gubernatorial election

none January 2025 September 2023 related races 1895 United States gubernatorial elections 1895 Rhode Island gubernatorial election Rhode Island 1882 Presidential no 1894 Rhode Island gubernatorial election 1894 1896 Rhode Island gubernatorial election 1896 April 3, 1895 file:CharlesWLippitt (cropped).jpg 150x150px Charles W. Lippitt Republican Party (United States) 25,098 56.89% File:George L. Littlefield from The Cotton Centennial, 1790-1890, p.96 (cropped).png George L. Littlefield Democratic Party (United States) 14,289 32.39% 3x4.svg Smith Quimby Prohibition Party (United States) 2,624 5.95% 250px County results 250px Municipality results 250px Lippitt: #FFB2B2 40–50% #E27F7F 50–60% #D75D5D 60–70% #D72F30 70–80% #C21B18 80-90%Littlefield: #A5B0FF 40–50% Governor Daniel Russell Brown Republican Party (United States) Charles W. Lippitt Republican Party (United States) The 1895 Rhode Island gubernatorial election was held on April 3, 1895. Republican nominee Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.89% of the vote. General election Candidates Major party candidates Charles W. Lippitt, Republican George L. Littlefield, Democratic Other candidates Smith Quimby, Prohibition George Boomer, Socialist Labor William Foster Jr., People's Results 1895 Rhode Island gubernatorial electionhttps://books.google.com/books?id=sKERAQAAMAAJ Congressional Quarterly's Guide to U.S. elections 9780871879967 July 18, 2020 Moore John Leo 1994 CQ Press Republican Party (United States) Charles W. Lippitt 25,098 56.89% Democratic Party (United States) George L. Littlefield 14,289 32.39% Prohibition Party Smith Quimby 2,624 5.95% Socialist Labor Party of America George Boomer 1,730 3.92% People's Party (United States) William Foster Jr. 379 0.86% 10,809 Republican Party (United States) References 1895 Rhode Island Category:1895 Rhode Island elections Category:April 1895 in the United States