1866 Rhode Island gubernatorial election

none January 2025 December 2025 ly 1866 Rhode Island gubernatorial election United States 1865 Presidential no 1865 Rhode Island gubernatorial election 1865 1867 Rhode Island gubernatorial election 1867 April 4, 1866 x150px Ambrose Burnside Republican Party (United States) 8,197 73.36% x150px Lyman Pierce Democratic Party (United States) 2,816 25.20% 1866 Rhode Island gubernatorial election results map by county.svg 250px County resultsBurnside: #D75D5D 60–70% #D72F30 70–80% #C21B18 80–90% Governor James Y. Smith Republican Party (United States) Ambrose Burnside Republican Party (United States) The 1866 Rhode Island gubernatorial election was held on April 4, 1866, in order to elect the governor of Rhode Island. Republican nominee and former Union Army Major General Ambrose Burnside defeated Democratic nominee Lyman Pierce.Ambrose Burnside https://www.nga.org/governor/ambrose-burnside/ 2024-04-07 National Governors Association General election On election day, April 4, 1866, Republican nominee Ambrose Burnside won the election by a margin of 5,381 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of governor. Burnside was sworn in as the 30th governor of Rhode Island on May 1, 1866.https://www.ourcampaigns.com/RaceDetail.html?RaceID=262518 RI Governor ourcampaigns.com July 26, 2005 2024-04-07 Results Rhode Island gubernatorial election, 1866 Republican Party (United States) Ambrose Burnside 8,197 73.36 Democratic Party (United States) Lyman Pierce 2,816 25.20 Scattering 160 1.44 11,221 100.00 Republican Party (United States) References Category:Rhode Island gubernatorial elections Category:1866 United States gubernatorial elections Category:April 1866 in the United States Category:1860s Rhode Island elections