1836 United States presidential election in Kentucky

none June 2025 September 2023 1836 United States presidential election 1836 United States presidential election in Kentucky presidential no 1832 United States presidential election in Kentucky 1832 1840 United States presidential election in Kentucky 1840 November 7–9, 1836 x200px William Henry Harrison by James Reid Lambdin, 1835 crop.jpg William Henry Harrison Whig Party (United States) Ohio Francis Granger 15 36,861 52.59% Martin Van Buren circa 1837 crop.jpg Martin Van Buren Democratic Party (United States) New York Richard Mentor Johnson 0 33,229 47.41% 1836 United States presidential election in Kentucky results map by county.svg 380px County results Harrison #FED463 50–60% #FE9929 60–70% #EC7014 70–80% #CC4C02 80–90% Van Buren #86b6f2 50–60% #4389e3 60–70% #1666cb 70–80% #0645b4 80–90% MI NY The 1836 United States presidential election in Kentucky was held between November 7 and 9, 1836 as part of the 1836 United States presidential election.Presidential Elections https://newspapers.library.in.gov/?a=d&d=WM18361112.1.3 Weekly Messenger November 12, 1836 Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President. Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%. Results 1836 United States presidential election in Kentucky1836 Presidential General Election Results - Kentucky http://uselectionatlas.org/RESULTS/state.php?year=1836&f=1&off=0&elect=0&fips=21&submit=Retrieve U.S. Election Atlas 4 August 2012PartyCandidateVotesPercentageElectoral votes Whig William Henry Harrison 36,861 52.59% 15 Democratic Martin Van Buren 33,229 47.41% 0 Totals 70,090 100.0% 15 References Kentucky 1836 Category:1836 Kentucky elections