1828 United States presidential election in Delaware

none June 2025 September 2023 1828 United States presidential election 1828 United States presidential election in Delaware presidential no 1824 United States presidential election in Delaware 1824 1832 United States presidential election in Delaware 1832 October 31 – December 2, 1828 x200px Portrait of John Quincy Adams (DRR) (Cropped).jpg John Quincy Adams National Republican Party (United States) Massachusetts Richard Rush 3 Andrew Jackson by Thomas Sully (Cropped).jpg Andrew Jackson Democratic Party (United States) Tennessee John C. Calhoun 0 The 1828 United States presidential election in Delaware took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President. Delaware cast three electoral votes for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote.1828 Presidential General Election Results http://uselectionatlas.org/RESULTS/national.php?year=1828&off=0&f=1 U.S. Election Atlas 13 April 2013 Results 1828 United States presidential election in DelawareElectoral Votes for President and Vice President 1821-1837 https://www.archives.gov/federal-register/electoral-college/votes/1821_1837.html#1828 National Archives and Records Administration 2 March 2013PartyCandidateVotesPercentageElectoral votes National Republican John Quincy Adams (incumbent) – – 3 Democratic Andrew Jackson – – 0 Totals – – 3 See also United States presidential elections in Delaware References Delaware 1828 Category:1828 Delaware elections