1899 Iowa gubernatorial election

none January 2025 January 2025 related races 1899 United States gubernatorial elections 1899 Iowa gubernatorial election Iowa Presidential no 1897 Iowa gubernatorial election 1897 1901 Iowa gubernatorial election 1901 November 7, 1899 File:Leslie Shaw, Bain photo portrait (cropped).jpg L. M. Shaw Republican Party (United States) 239,464 55.26% Frederick Edward White (1).png Frederick Edward White Democratic Party (United States) 183,301 42.30% 1899 Iowa gubernatorial election results map by county.svg 240px County results Shaw: #FFB2B2 40–50% #e27f7f 50–60% #d75d5d 60–70% #D72F30 70–80%White: #A5B0FF 40–50% #7996E2 50–60% Governor L. M. Shaw Republican Party (United States) L. M. Shaw Republican Party (United States) The 1899 Iowa gubernatorial election was held on November 7, 1899. Incumbent Republican L. M. Shaw defeated Democratic nominee Frederick Edward White with 55.26% of the vote. General election Candidates Major party candidates L. M. Shaw, Republican Frederick Edward White, Democratic Other candidates Marshall W. Atwood, Prohibition Charles Lloyd, People's M. J. Kremer, Socialist Labor C. C. Heacock, United Christian Results 1899 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 August 7, 2020 Kalb Deborah 24 December 2015 Republican Party (United States) L. M. Shaw (incumbent) 239,464 55.26% Democratic Party (United States) Frederick Edward White 183,301 42.30% Prohibition Party Marshall W. Atwood 7,639 1.76% People's Party (United States) Charles Lloyd 1,698 0.39% Socialist Labor Party of America M. J. Kremer 757 0.18% Independent politician C. C. Heacock 484 0.11% 56,163 Republican Party (United States) References collapsed 1899 Iowa Category:November 1899 in the United States Category:1899 in Iowa