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1918 Rhode Island gubernatorial election
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1918 Rhode Island gubernatorial election Rhode Island Presidential no 1916 Rhode Island gubernatorial election 1916 1920 Rhode Island gubernatorial election 1920 November 5, 1918 File:R. Livingston Beeckman - War Records of the Knickerbocker Club.jpg Robert Livingston Beeckman Republican Party (United States) 42,682 53.11% File:Alberic A. Archambault.png Alberic A. Archambault Democratic Party (United States) 36,031 44.84% 250px County results 250px Municipality results 250px Beeckman: #FFB2B2 40–50% #E27F7F 50–60% #D75D5D 60–70% #D72F30 70–80% #C21B18 80–90% #A80000 >90%Archambault: #A5B0FF 40–50% #7996E2 50–60% Governor Robert Livingston Beeckman Republican Party (United States) Robert Livingston Beeckman Republican Party (United States)
The 1918 Rhode Island gubernatorial election was held on November 5, 1918. Incumbent Republican Robert Livingston Beeckman defeated Democratic nominee Alberic A. Archambault with 53.11% of the vote.
General election
Candidates
Major party candidates
Robert Livingston Beeckman, Republican
Alberic A. Archambault, Democratic
Other candidates
Ernest Sherwood, Socialist
Results
1918 Rhode Island gubernatorial electionhttps://books.google.com/books?id=sKERAQAAMAAJ Congressional Quarterly's Guide to U.S. elections 9780871879967 May 20, 2020 Moore John Leo 1994 CQ Press
Republican Party (United States) Robert Livingston Beeckman (incumbent) 42,682 53.11%
Democratic Party (United States) Alberic A. Archambault 36,031 44.84%
Socialist Party USA Ernest Sherwood 1,648 2.05%
6,651
Republican Party (United States)
References
1918
Rhode Island
Gubernatorial
Category:November 1918 in the United States