1840 United States presidential election in Rhode Island

none June 2025 September 2023 1840 United States presidential election 1840 United States presidential election in Rhode Island Rhode Island presidential no 1836 United States presidential election in Rhode Island 1836 1844 United States presidential election in Rhode Island 1844 November 2, 1840 x200px William Henry Harrison Portrait (3x4 cropped).jpg William Henry Harrison Whig Party (United States) Ohio John Tyler 4 5,278 61.22% Bust Portrait of Martin Van Buren (Cropped).jpg Martin Van Buren Democratic Party (United States) New York none 0 3,301 38.29% 1840 United States presidential election in Rhode Island results map by county.svg 250px County results Harrison #FED463 50–60% #FE9929 60–70% #EC7014 70–80% President Martin Van Buren Democratic Party (United States) William Henry Harrison Whig Party (United States) NH VA A presidential election was held in Rhode Island on November 2, 1840 as part of the 1840 United States presidential election.Dubin Michael J. United States Presidential Elections, 1788–1860: The Official Results by County and State 2002 McFarland & Co. Jefferson, NC xvi Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. Rhode Island voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Rhode Island by a margin of 22.93%. With 61.22% of the popular vote, Rhode Island would be Harrison's third strongest state in the 1840 election after Kentucky and Vermont.https://uselectionatlas.org/RESULTS/stats.php?year=1840&f=1&off=0&elect=0 1840 Presidential Election Statistics Dave Leip’s Atlas of U.S. Presidential Elections 2018-03-05 Results 1840 United States presidential election in Rhode Island1840 Presidential General Election Results - Rhode Island http://uselectionatlas.org/RESULTS/state.php?year=1840&f=1&off=0&elect=0&fips=44&submit=Retrieve U.S. Election Atlas 23 December 2013 Whig Party (United States) William Henry Harrison Ohio John Tyler Virginia 5,278 61.22% 4 100.00% Democratic Party (United States) Martin Van Buren New York Richard Mentor Johnson Kentucky 3,301 38.29% 0 0.00% Liberty Party (US, 1840) James G. Birney New York Thomas Earle Pennsylvania 42 0.49% 0 0.00% 8,621 100.00% 4 100.00% See also United States presidential elections in Rhode Island References Rhode Island 1840 Category:1840 Rhode Island elections