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1920 Iowa gubernatorial election
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1920 Iowa gubernatorial election Iowa Presidential no 1918 Iowa gubernatorial election 1918 1922 Iowa gubernatorial election 1922 November 2, 1920 Nathan E. Kendall (1).png Nathan E. Kendall Republican Party (United States) 513,118 58.66% Clyde Herring (1).jpg Clyde L. Herring Democratic Party (United States) 338,108 38.65% 1920 Iowa gubernatorial election results map by county.svg 240px County resultsKendall: #FFB2B2 40–50% #e27f7f 50–60% #d75d5d 60–70% #d72f30 70–80% Herring: #7996e2 50–60% Governor William L. Harding Republican Party (United States) Nathan E. Kendall Republican Party (United States)
The 1920 Iowa gubernatorial election was held on November 2, 1920. Republican nominee Nathan E. Kendall defeated Democratic nominee Clyde L. Herring with 58.66% of the vote.
General election
Candidates
Major party candidates
Nathan E. Kendall, Republican
Clyde L. Herring, Democratic
Other candidates
George J. Peck, Socialist
Mathis Faber, Farmer–Labor
J. Jay Hisel, Socialist Labor
Results
1920 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 June 30, 2020 Kalb Deborah 24 December 2015
Republican Party (United States) Nathan E. Kendall 513,118 58.66%
Democratic Party (United States) Clyde L. Herring 338,108 38.65%
Socialist Party of America George J. Peck 13,671 1.56%
Farmer–Labor Party Mathis Faber 9,153 1.05%
Socialist Labor Party of America J. Jay Hisel 760 0.09%
175,010
Republican Party (United States)
References
1920
Iowa
Gubernatorial