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1880 Rhode Island gubernatorial election
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1880 Rhode Island gubernatorial election Rhode Island 1877 Presidential no 1879 Rhode Island gubernatorial election 1879 1881 Rhode Island gubernatorial election 1881 April 7, 1880 x150px Alfred H. Littlefield Republican Party (United States) 10,224 44.82% x150px Horace A. Kimball Democratic Party (United States) 7,440 32.62% x150px Albert C. Howard Independent Republican (United States) 5,047 22.13% 1880 Rhode Island gubernatorial election results map by county.svg 225px County resultsLittlefield: #FFB2B2 40–50% #E27F7F 50–60% Governor Charles C. Van Zandt Republican Party (United States) Alfred H. Littlefield Republican Party (United States)
The 1880 Rhode Island gubernatorial election was held on April 7, 1880. Republican nominee Alfred H. Littlefield defeated Democratic nominee Horace A. Kimball with 44.82% of the vote.
General election
Candidates
Major party candidates
Alfred H. Littlefield, Republican
Horace A. Kimball, Democratic
Other candidates
Albert C. Howard, Independent Republican
Results
1880 Rhode Island gubernatorial electionhttps://books.google.com/books?id=sKERAQAAMAAJ Congressional Quarterly's Guide to U.S. elections 9780871879967 October 27, 2020 Moore John Leo 1994 CQ Press
Republican Party (United States) Alfred H. Littlefield 10,224 44.82%
Democratic Party (United States) Horace A. Kimball 7,440 32.62%
Independent Republican (United States) Albert C. Howard 5,047 22.13%
2,784
Republican Party (United States)
References
1880
Rhode Island
Gubernatorial
Category:April 1880 in the United States