1896 Rhode Island gubernatorial election

none January 2025 September 2023 1896 Rhode Island gubernatorial election Rhode Island 1882 Presidential no 1895 Rhode Island gubernatorial election 1895 1897 Rhode Island gubernatorial election 1897 April 1, 1896 File:CharlesWLippitt (cropped).jpg Charles W. Lippitt Republican Party (United States) 28,472 56.40% 3x4.svg George L. Littlefield Democratic Party (United States) 17,061 33.79% 3x4.svg 150x150px Thomas H. Peabody Prohibition Party (United States) 2,950 5.84% 1896 Rhode Island gubernatorial election results map by county.svg 250px County resultsLippitt: #e27f7f 50–60% #D75D5D 60–70% Governor Charles W. Lippitt Republican Party (United States) Charles W. Lippitt Republican Party (United States) The 1896 Rhode Island gubernatorial election was held on April 1, 1896. Incumbent Republican Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.40% of the vote. General election Candidates Major party candidates Charles W. Lippitt, Republican George L. Littlefield, Democratic Other candidates Thomas H. Peabody, Prohibition Edward W. Theinert, Socialist Labor Henry A. Burlingame, People's Results 1896 Rhode Island gubernatorial electionhttps://books.google.com/books?id=sKERAQAAMAAJ Congressional Quarterly's Guide to U.S. elections 9780871879967 July 18, 2020 Moore John Leo 1994 CQ Press Republican Party (United States) Charles W. Lippitt (incumbent) 28,472 56.40% Democratic Party (United States) George L. Littlefield 17,061 33.79% Prohibition Party Thomas H. Peabody 2,950 5.84% Socialist Labor Party of America Edward W. Theinert 1,272 2.52% People's Party (United States) Henry A. Burlingame 730 1.45% 11,411 Republican Party (United States) References 1896 Rhode Island Gubernatorial Category:April 1896 in North America