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1916 Iowa gubernatorial election
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1916 Iowa gubernatorial election Iowa Presidential no 1914 Iowa gubernatorial election 1914 1918 Iowa gubernatorial election 1918 November 7, 1916 William Lloyd Harding in 1915 (1).jpg William L. Harding Republican Party (United States) 313,586 61.03% E.T. Meredith, ggbain.16011u (1).jpg Edwin T. Meredith Democratic Party (United States) 186,832 36.36% 1916 Iowa gubernatorial election results map by county.svg 240px County results
Harding: #FFB2B2 40–50% #e27f7f 50–60% #d75d5d 60–70% #D72F30 70–80%Meredith: #7996E2 50–60% Governor George W. Clarke Republican Party (United States) William L. Harding Republican Party (United States)
The 1916 Iowa gubernatorial election was held on November 7, 1916. Republican nominee William L. Harding defeated Democratic nominee Edwin T. Meredith with 61.03% of the vote.
General election
Candidates
Major party candidates
William L. Harding, Republican
Edwin T. Meredith, Democratic
Other candidates
John W. Bennett, Socialist
Oren D. Ellett, Prohibition
Stephen H. Bashor, Progressive
Arthur S. Dowler, Socialist Labor
Results
1916 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 July 2, 2020 Kalb Deborah 24 December 2015
Republican Party (United States) William L. Harding 313,586 61.03%
Democratic Party (United States) Edwin T. Meredith 186,832 36.36%
Socialist Party of America John W. Bennett 8,200 1.60%
Prohibition Party Oren D. Ellett 2,880 0.56%
Bull Moose Party Progressive Stephen H. Bashor 2,035 0.40%
Socialist Labor Party of America Arthur S. Dowler 315 0.06%
126,754
Republican Party (United States)
References
1916
Iowa
Gubernatorial