1894 United States House of Representatives election in Wyoming

none February 2026 September 2023 1894 United States House of Representatives election in Wyoming Wyoming presidential No 1892 United States House of Representatives election in Wyoming 1892 1896 United States House of Representatives election in Wyoming 1896 1894 11 06 150x150px Frank Wheeler Mondell Republican Party (United States) 10,068 52.64% 150x150px Henry A. Coffeen Democratic Party (United States) 6,152 32.17% Shakespeare E. Sealey People's Party (United States) 2,906 15.19% File:1894 Wyoming At-Large election results.svg 250px County resultsMondell: #f1b5b2 40–50%#ed8883 50–60% #e55751 60–70% Coffeen: #dee8fb 30–40% #808080 No Data U.S. Representative Henry A. Coffeen Democratic Party (United States) Frank Wheeler Mondell Republican Party (United States) The Wyoming United States House election for 1894 was held on November 6, 1894. Republican Frank Wheeler Mondell defeated Democratic incumbent Henry A. Coffeen and Populist Shakespeare E. Sealey with 52.64% of the vote making Coffeen the second incumbent Representative from Wyoming to lose reelection. Results United States House of Representatives election in Wyoming, 1894United States House of Representatives election in Wyoming, 1894 https://www.ourcampaigns.com/RaceDetail.html?RaceID=253643 Frank Wheeler Mondell Republican Party (United States) 10,068 52.64% Henry A. Coffeen (inc.) Democratic Party (United States) #3333FF 6,152 32.17% Shakespeare E. Sealey People's Party (United States) 2,906 15.19% 19,126 100% References 1894 Wyoming Category:1894 Wyoming elections