1824 United States presidential election in Delaware

none June 2025 September 2023 1824 United States presidential election 1824 United States presidential election in Delaware presidential no 1820 United States presidential election in Delaware 1820 1828 United States presidential election in Delaware 1828 October 26 – December 2, 1824 x200px William Harris Crawford by John Wesley Jarvis (PAFA) (3x4 cropped).jpg William H. Crawford 68C468 Democratic-Republican Party Georgia Nathaniel Macon 2 John quincy adams - thomas sully (Cropped).jpg John Quincy Adams FF9955 Democratic-Republican Party Massachusetts John C. Calhoun 1 President James Monroe Democratic-Republican Party John Quincy Adams Democratic-Republican Party The 1824 United States presidential election in Delaware took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President. During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Delaware cast two electoral votes for William H. Crawford and one for John Quincy Adams. Results 1824 United States presidential election in DelawareElectoral Votes for President and Vice President 1821-1837 https://www.archives.gov/federal-register/electoral-college/votes/1821_1837.html#1824 National Archives and Records Administration 28 February 2013PartyCandidateVotesPercentageElectoral votes Democratic-Republican William H. Crawford 2 Democratic-Republican John Quincy Adams 1 Democratic-Republican Henry Clay 0 Democratic-Republican Andrew Jackson 0 Totals 3 See also United States presidential elections in Delaware References Delaware 1824 Category:1824 Delaware elections