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1877 Iowa gubernatorial election
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1877 Iowa gubernatorial election Iowa Presidential no 1875 Iowa gubernatorial election 1875 1879 Iowa gubernatorial election 1879 October 9, 1877 File:John Henry Gear - Senator.jpg 150x150px John H. Gear Republican Party (United States) 121,316 49.39% File:John p irish.jpg John P. Irish Democratic Party (United States) 79,304 32.29% File:Daniel P. Stubbs - History of Iowa (cropped).jpg Daniel P. Stubbs Greenback Party 34,316 13.97% 1877 Iowa gubernatorial election results map by county.svg 240px County results
Gear: #FFC8CD 30–40% #FFB2B2 40–50% #e27f7f 50–60% #d75d5d 60–70% #D72F30 70–80% #C21B18 80–90% #A80000 90–100%Irish: #BDD3FF 30–40% #A5B0FF 40–50% #7996E2 50–60% #6674DE 60–70%Stubbs: #73D873 50–60% Governor Joshua G. Newbold Republican Party (United States) John H. Gear Republican Party (United States)
The 1877 Iowa gubernatorial election was held on October 9, 1877. Republican nominee John H. Gear defeated Democratic nominee John P. Irish with 49.39% of the vote.
General election
Candidates
Major party candidates
John H. Gear, Republican
John P. Irish, Democratic
Other candidates
Daniel P. Stubbs, Greenback
Elias Jessup, Prohibition
Results
1877 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 September 21, 2020 Kalb Deborah 24 December 2015
Republican Party (United States) John H. Gear 121,316 49.39%
Democratic Party (United States) John P. Irish 79,304 32.29%
Greenback Party Daniel P. Stubbs 34,316 13.97%
Prohibition Party Elias Jessup 10,565 4.30%
42,012
Republican Party (United States)
References
1877
Iowa
Category:1877 Iowa elections
Category:October 1877 in the United States
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