1796 United States presidential election in Delaware

none June 2025 December 2025 ly 1796 United States presidential election 1796 United States presidential election in Delaware presidential no 1792 United States presidential election in Delaware 1792 1800 United States presidential election in Delaware 1800 November 4 – December 7, 1796 x200px File:Official Presidential portrait of John Adams (by John Trumbull, circa 1792) (farther 3x4 cropped) (cropped).jpg John Adams Federalist Party (United States) Massachusetts Thomas Pinckney 3 100.00% File:ThomasJeffersonStateRoomPortrait (cropped2).jpg Thomas Jefferson Democratic-Republican Party (United States) Virginia Aaron Burr 0 0.00% A presidential election was held in Delaware between November 4 and December 7, 1796, as part of the 1796 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president. Delaware cast three electoral votes for the Federalist candidate and incumbent vice president John Adams over the Democratic-Republican candidate Thomas Jefferson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for vice president were cast for Adams' running mate Thomas Pinckney from South Carolina.1796 Presidential General Election Results https://uselectionatlas.org/RESULTS/ U.S. Election Atlas 2023-07-09 Results 1796 United States presidential election in Delaware1796 Presidential Election https://www.270towin.com/1796_Election/index.html 270towin.com 2023-07-09PartyCandidateVotesPercentageElectoral votes Federalist John Adams – 100.00% 3 Democratic-Republican Thomas Jefferson – 0.00% 0 Totals – – 3 See also United States presidential elections in Delaware References Category:1796 United States presidential election by state or territory Category:United States presidential elections in Delaware Category:1796 Delaware elections