1828 United States presidential election in New Jersey

none June 2025 September 2023 1828 United States presidential election 1828 United States presidential election in New Jersey New Jersey presidential no 1824 United States presidential election in New Jersey 1824 1832 United States presidential election in New Jersey 1832 October 31 – December 2, 1828 x200px Portrait of John Quincy Adams (DRR) (Cropped).jpg John Quincy Adams National Republican Party (United States) Massachusetts Richard Rush 8 23,753 52.12% Andrew Jackson by Thomas Sully (Cropped).jpg Andrew Jackson Democratic Party (United States) Tennessee John C. Calhoun 0 21,809 47.86% 1828 United States presidential election in New Jersey results map by county.svg 150px County results Adams #FED463 50–60% #FE9929 60–70% #EB7012 70–80% Jackson #86B6F2 50–60% #4389E3 60–70% #1666CB 70–80% President John Quincy Adams National Republican Party (United States) Andrew Jackson Democratic Party (United States) The 1828 United States presidential election in New Jersey took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President. New Jersey voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won New Jersey by a narrow margin of 4.26%. Results 1828 United States presidential election in New Jersey1828 Presidential General Election Results - New Jersey http://uselectionatlas.org/RESULTS/state.php?year=1828&f=1&off=0&elect=0&fips=34&submit=Retrieve U.S. Election Atlas 28 February 2013PartyCandidateVotesPercentageElectoral votes National Republican John Quincy Adams (incumbent) 23,753 52.12% 8 Democratic Andrew Jackson 21,809 47.86% 0 N/A Other 8 0.02% 0 Totals 45,570 100.0% 8 See also United States presidential elections in New Jersey References New Jersey 1828 Category:1828 New Jersey elections