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1796 United States presidential election in Rhode Island
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1796 United States presidential election
1796 United States presidential election in Rhode Island Rhode Island 1796 presidential no 1792 United States presidential election in Rhode Island 1792 1800 United States presidential election in Rhode Island 1800 November 4 – December 7, 1796 x200px File:Official Presidential portrait of John Adams (by John Trumbull, circa 1792) (farther 3x4 cropped) (cropped).jpg John Adams Federalist Party (United States) Massachusetts Thomas Pinckney 4 100.00% President George Washington Independent (politician) John Adams Federalist Party (United States)
A presidential election was held in Rhode Island between November 4 to December 7, 1796, as part of the 1796 United States presidential election. Voters chose four representatives, or electors to the Electoral College who voted for president and vice president.
During this election, Rhode Island cast its four electoral votes for John Adams.A New Nation Votes https://elections.lib.tufts.edu/catalog/1j92g900m 2024-08-29 elections.lib.tufts.edu
Results
1796 United States presidential election in Rhode IslandA New Nation Votes https://elections.lib.tufts.edu/?f%5Boffice_id_ssim%5D%5B%5D=ON056&range%5Bpub_date_facet_isim%5D%5Bbegin%5D=1796&range%5Bpub_date_facet_isim%5D%5Bend%5D=1796 2024-08-29 elections.lib.tufts.eduDubin Michael J. United States Presidential Elections, 1788-1860: The Official Results by County and State 2002 McFarland 0-7864-1017-5 Jefferson, North Carolina xii6–8PartyCandidateVotesPercentageElectoral votesFederalistJohn Adams——4Totals——4
See also
United States presidential elections in Rhode Island
References
Category:1796 United States presidential election by state or territory
Category:United States presidential elections in Rhode Island
Category:1796 Rhode Island elections