1856 United States presidential election in Arkansas

none June 2025 January 2025 1856 United States presidential election 1856 United States presidential election in Arkansas presidential no 1852 United States presidential election in Arkansas 1852 November 4, 1856 1860 United States presidential election in Arkansas 1860 x200px James Buchanan (cropped).jpg James Buchanan Democratic Party (United States) Pennsylvania John C. Breckinridge 4 21,910 67.12% Fillmore (cropped).jpg Millard Fillmore Know Nothing New York Andrew Jackson Donelson 0 10,732 32.88% 1856 United States presidential election in Arkansas results map by county.svg 300px County results Buchanan #86b6f2 50–60% #4389e3 60–70% #1666cb 70–80% #0645b4 80–90% #002b84 90–100% Fillmore #C88FE4 50–60% No Vote: #808080 President Franklin Pierce Democratic Party (United States) James Buchanan Democratic Party (United States) The 1856 United States presidential election in Arkansas was held on November 4, 1856. Arkansas voters chose four electors to represent the state in the Electoral College, which chose the president and vice president. Arkansas voted for the Democratic nominee James Buchanan, who received 67% of the vote.http://uselectionatlas.org/RESULTS/state.php?year=1856&fips=5&f=0&off=0&elect=0 1856 Presidential General Election Results - Arkansas David Leip's U.S. Election Atlas 2017-06-05 Buchanan won every county that has data available except for Sebastian. Republican Party nominee John C. Frémont was not on the ballot. Results 1856 United States presidential election in Arkansas James Buchanan Democratic Party (United States) #3333FF 21,910 67.12% Millard Fillmore Know Nothing #D99FE8 10,732 32.88% 32,642 100% See also United States presidential elections in Arkansas References 1856 Arkansas Category:1856 in Arkansas