1867 Iowa gubernatorial election

none January 2025 September 2023 1867 Iowa gubernatorial election Iowa Presidential no 1865 Iowa gubernatorial election 1865 1869 Iowa gubernatorial election 1869 October 8, 1867 x150px Samuel Merrill Republican Party (United States) 90,204 58.88% x150px Charles Mason Democratic Party (United States) 62,966 41.10% 1867 Iowa gubernatorial election results map by county.svg 240px County results Merrill: #e27f7f 50–60% #d75d5d 60–70% #D72F30 70–80% #C21B18 80–90% #A80000 90–100%Mason: #7996E2 50–60% #6674DE 60–70%No Data/Votes: #808080 Governor William M. Stone Republican Party (United States) Samuel Merrill Republican Party (United States) The 1867 Iowa gubernatorial election was held on October 8, 1867. Republican nominee Samuel Merrill defeated Democratic nominee Charles Mason with 58.88% of the vote. General election Candidates Samuel Merrill, Republican Charles Mason, Democratic Results 1867 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 June 5, 2021 Kalb Deborah 24 December 2015 Republican Party (United States) Samuel Merrill 90,204 58.88% Democratic Party (United States) Charles Mason 62,966 41.10% 27,238 Republican Party (United States) References 1867 Iowa Category:1867 Iowa elections Category:October 1867 in the United States collapsed