1888 Belgian general election

none 1888 Belgian general election Belgium parliamentary 1886 Belgian general election 1886 1890 Belgian general election 1890 69 of the 138 seats in the Chamber of Representatives 70 1888 06 12 yes 150x150px Auguste Beernaert Candidate for PM Catholic Party (Belgium) 98 seats 66 98 31,273 58.44% 100x100px Liberal Party (Belgium) 40 seats 3 40 19,967 37.31% Government Government after election Beernaert Catholic Party (Belgium) Beernaert Catholic Party (Belgium) Partial general elections were held in Belgium on 12 June 1888.Codebook Constituency-level Elections Archive, 2003Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105 The result was a victory for the Catholic Party, which won 98 of the 138 seats in the Chamber of Representatives and 47 of the 69 seats in the Senate. Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. Results Chamber of Representatives File:Belgian Chamber 1886.svg Won Total +/– Catholic Party 31273 66 98 0 Liberal Party 19967 3 40 0 Others 2277 0 0 New 0 53517 73276 Mackie & Rose,Thomas T. Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51 Sternberger et al. Senate 250px Catholic Party 47 Liberal Party 18 Independents 4 Sternberger et al. References Category:1880s elections in Belgium General Belgium Belgium