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1890 New Hampshire gubernatorial election
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1890 New Hampshire gubernatorial election New Hampshire Presidential no 1888 New Hampshire gubernatorial election 1888 1892 New Hampshire gubernatorial election 1892 November 4, 1890 x150px Hiram A. Tuttle Republican Party (United States) 42,479 49.26% x150px Charles H. Amsden Democratic Party (United States) 42,386 49.15% x245px County results x245px Municipality results Tuttle: #FFB2B2 40-50% #e27f7f 50–60% #d75d5d 60–70% #d72f30 70–80% #c21b18 80–90%Amsden: #A5B0FF 40-50% #7996e2 50–60% #6674de 60–70% #584cde 70–80% #3933e5 80–90% #0D0596 >90%Tie: #D2B1D9 40-50% #ae8bb1 50% Governor David H. Goodell Republican Party (United States) Hiram A. Tuttle Republican Party (United States)
The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.
General election
Candidates
Major party candidates
Hiram A. Tuttle, Republican
Charles H. Amsden, Democratic
Other candidates
Josiah M. Fletcher, Prohibition
Results
1890 New Hampshire gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1714 Guide to U.S. Elections 24 December 2015 9781483380353 2020-07-16 Kalb Deborah
Republican Party (United States) Hiram A. Tuttle 42,479 49.26%
Democratic Party (United States) Charles H. Amsden 42,386 49.15%
Prohibition Party Josiah M. Fletcher 1,343 1.56%
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Republican Party (United States)
References
1890
New Hampshire
Gubernatorial
Category:November 1890 in the United States