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1895 Iowa gubernatorial election
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1895 Iowa gubernatorial election Iowa Presidential no 1893 Iowa gubernatorial election 1893 1897 Iowa gubernatorial election 1897 November 5, 1895 File:FrancisMDrake.jpg 150x150px Francis M. Drake Republican Party (United States) 208,708 52.00% File:Washington Irving Babb.jpg Washington I. Babb Democratic Party (United States) 149,428 37.23% 3x4.svg Sylvanus B. Crane, Jr. People's Party (United States) 32,189 8.02% 1895 Iowa gubernatorial election results map by county.svg 240px County resultsDrake: #ffb2b2 40–50% #e27f7f 50–60% #d75d5d 60–70% #d72f30 70–80%Babb: #a5b0ff 40–50% #7996e2 50–60% #6674de 60–70%Crane: #AFE9AF 40–50% Governor Frank D. Jackson Republican Party (United States) Francis M. Drake Republican Party (United States)
The 1895 Iowa gubernatorial election was held on November 5, 1895. Republican nominee Francis M. Drake defeated Democratic nominee Washington I. Babb with 52.00% of the vote.
General election
Candidates
Major party candidates
Francis M. Drake, Republican
Washington I. Babb, Democratic
Other candidates
Sylvanus B. Crane, Jr., People's
Francis Bacon, Prohibition
Results
1895 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 August 8, 2020 Kalb Deborah 24 December 2015
Republican Party (United States) Francis M. Drake 208,708 52.00%
Democratic Party (United States) Washington I. Babb 149,428 37.23%
People's Party (United States) Sylvanus B. Crane, Jr. 32,189 8.02%
Prohibition Party Francis Bacon 11,014 2.74%
59,280
Republican Party (United States) +2.26%
References
1895
Iowa