1903 Iowa gubernatorial election

none January 2025 January 2025 related races 1903 United States gubernatorial elections 1903 Iowa gubernatorial election Iowa Presidential no 1901 Iowa gubernatorial election 1901 1906 Iowa gubernatorial election 1906 November 3, 1903 File:A.B. Cummins LCCN2014701713 (1).jpg Albert B. Cummins Republican Party (United States) 238,804 57.14% 3x4.svg J. B. Sullivan Democratic Party (United States) 159,725 38.22% 1903 Iowa gubernatorial election results map by county.svg 240px County results Cummins: #FFB2B2 40–50% #e27f7f 50–60% #d75d5d 60–70% #D72F30 70–80% #C21B18 80–90%Sullivan: #A5B0FF 40–50% #7996E2 50–60% Governor Albert B. Cummins Republican Party (United States) Albert B. Cummins Republican Party (United States) The 1903 Iowa gubernatorial election was held on November 3, 1903. Incumbent Republican Albert B. Cummins defeated Democratic nominee J. B. Sullivan with 57.14% of the vote. General election Candidates Major party candidates Albert B. Cummins, Republican J. B. Sullivan, Democratic Other candidates John F. Hanson, Prohibition John M. Work, Socialist Luman Hamlin Weller, People's Results 1903 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 August 3, 2020 Kalb Deborah 24 December 2015 Republican Party (United States) Albert B. Cummins (incumbent) 238,804 57.14% Democratic Party (United States) J. B. Sullivan 159,725 38.22% Prohibition Party John F. Hanson 12,375 2.96% Socialist Party of America John M. Work 6,421 1.54% People's Party (United States) Luman Hamlin Weller 594 0.14% 79,079 Republican Party (United States) References 1903 Iowa