1891 Iowa gubernatorial election

none January 2025 January 2025 related races 1891 United States gubernatorial elections 1891 Iowa gubernatorial election Iowa Presidential no 1889 Iowa gubernatorial election 1889 1893 Iowa gubernatorial election 1893 November 3, 1891 File:Horace Boies signed (cropped).jpg 150x150px Horace Boies Democratic Party (United States) 207,594 49.40% 3x4.svg Hiram C. Wheeler Republican Party (United States) 199,381 47.45% 1891 Iowa gubernatorial election results map by county.svg 240px County results Boies: #A5B0FF 40–50% #7996E2 50–60% #6674DE 60–70% #584CDE 70–80%Wheeler: #FFB2B2 40–50% #e27f7f 50–60% #d75d5d 60–70%Westfall: #D7F4D7 30–40% Governor Horace Boies Democratic Party (United States) Horace Boies Democratic Party (United States) The 1891 Iowa gubernatorial election was held on November 3, 1891. Incumbent Democrat Horace Boies defeated Republican nominee Hiram C. Wheeler with 49.40% of the vote. General election Candidates Major party candidates Horace Boies, Democratic Hiram C. Wheeler, Republican Other candidates A. J. Westfall, People's Isaac T. Gibson, Prohibition Results 1891 Iowa gubernatorial electionhttps://books.google.com/books?id=9CZECwAAQBAJ&pg=PA1693 Guide to U.S. Elections 9781483380353 August 9, 2020 Kalb Deborah 24 December 2015 Democratic Party (United States) Horace Boies (incumbent) 207,594 49.40% Republican Party (United States) Hiram C. Wheeler 199,381 47.45% People's Party (United States) A. J. Westfall 12,303 2.93% Prohibition Party Isaac T. Gibson 915 0.22% 8,213 Democratic Party (United States) References 1891 Iowa