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1800 United States presidential election in New Jersey
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1800 United States presidential election
1800 United States presidential election in New Jersey New Jersey presidential no 1796 United States presidential election in New Jersey 1796 1804 United States presidential election in New Jersey 1804 October 31 – December 3, 1800 x200px File:Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg John Adams Federalist Party (United States) Massachusetts 7 100.00% CharlesCPinckney (cropped).png Charles Cotesworth Pinckney Federalist Party (United States) South Carolina 7 – President John Adams Federalist Party (United States) Thomas Jefferson Democratic-Republican Party
A presidential election was held in New Jersey between October 31 and December 3, 1800, as part of the 1800 United States presidential election. The state legislature chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, New Jersey cast seven electoral votes for incumbent Federalist President John Adams.Dubin Michael J. United States Presidential Elections, 1788-1860: The Official Results by County and State McFarland & Company 2002 9780786410170 Jefferson 9 However, Adams would lose to Democratic-Republican Party candidate Thomas Jefferson nationally.
See also
United States presidential elections in New Jersey
References
New Jersey
1800
Category:1800 New Jersey elections